bpd19, you are asking a very broad question. You need much more info to come up with the answer. Here is an example
A vehicle traveling 50 miles per hours is traveling 73.5 feet per second (1.47 X M.P.H.)
Perception time is 1.5 seconds
We multiply 73.5 X 1.5 = 110 feet
D=S²/(30*f)
D=50²/(30*.75)
D=111 feet
Total Distance is 110 feet + 111 ft = 221 Feet
Remember f is the drag factor. I used .75 for average travelled dry pavement, that can change dramatically based on the drag factor. You have to either do test skids or use a drag sled. Also you should computer for m=grade and super-elevation to get an accurate number.
Hope this helps, recon class!!
A vehicle traveling 50 miles per hours is traveling 73.5 feet per second (1.47 X M.P.H.)
Perception time is 1.5 seconds
We multiply 73.5 X 1.5 = 110 feet
D=S²/(30*f)
D=50²/(30*.75)
D=111 feet
Total Distance is 110 feet + 111 ft = 221 Feet
Remember f is the drag factor. I used .75 for average travelled dry pavement, that can change dramatically based on the drag factor. You have to either do test skids or use a drag sled. Also you should computer for m=grade and super-elevation to get an accurate number.
Hope this helps, recon class!!
